![]() The valence-shell electron-pair repulsion (VSEPR) model allows us to predict which of the possible structures is actually observed in most cases. Note: Nitrogen being a non-metal has five electrons in its outermost shell and requires only three electrons to complete its octet and acquire stable electronic configuration of the nearest noble gas So, nitrogen has a strong tendency to gain three electrons from the other electron donating species and thus, it acts as a strong Lewis acid. In ammonia, the central atom, nitrogen, has five valence electrons and each hydrogen donates one valence electron, producing the Lewis electron structure. ![]() Thus, the total number of valence electrons present in nitrogen atoms is five. The number of electrons present in an atom is always equal to the atomic number of that very element.Īnd The electrons which are present in the outermost valence shell of an atom are called the valence electrons.įrom the electronic configuration of the nitrogen atom, we come to know that the number of electrons present in the outermost shell i.e., 2rd shell is 5 electrons. It has the electronic configuration as: $1$. You can determine the number of valence electrons an element has by looking at the Periodic Table. It has an atomic number as 7 and the mass number as 14. It lies in the 15th group and 2nd period of the periodic table. Nitrogen is a non-metal and a gas which belongs to the p-block elements of the periodic table. Hint To find the number of valence electrons in nitrogen atom, you should first know that how many electrons are present in nitrogen and then, calculate the total number of electrons present in the s, p and d-orbitals to get the valence electrons.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |